- Compute the capacitance of an isolated conducting sphere of radius
. Hint: Consider the other electrode to be a spherical shell
surrounding the conducting sphere at very large radius.
- Given a parallel plate capacitor with plate area
, charge
on the plates, and the possibly variable plate separation
:
- Is the force between the plates attractive or repulsive?
- Compute the magnitude of the force of each plate on the other.
Hint: You know both the electric field and the charge.
- Make an alternate computation of the force as follows: Compute the
energy
in the electric field between the plates. The force
is
.
- You probably found that the above two calculations of the force didn't
agree. Which is correct? Explain. Hint: In doing part (b), what
part of the electric field acting on (say) the negative charge is due
to itself, and what part is due to the positive charge? Only the
latter part can exert a net force on the negative charge!
- Compute the circulation of the vector field around the illustrated
circle in the left panel of figure 17.3. Assume that the
magnitude of the vector field equals
where
is a constant.
- Compute the circulation of the vector field around the illustrated
rectangle in the right panel of figure 17.3. Assume that
the
component of the vector field equals
where
is a
constant.
- The solar wind consists of a plasma (a gas consisting of charged
particles with equal amounts of positive and negative charge)
streaming out from the sun. In certain sectors of the solar wind the
magnetic field points away from the sun while in other sectors it
points toward the sun. What is the magnitude and direction of the
current flowing through the loop defined by the dashed rectangle which
spans a sector boundary as shown in figure 17.8?
Figure 17.8:
Magnetic field at a solar wind sector boundary.
 |
- A superconducting parallel plate inductor with plate dimensions
by
and spacing
is held
together by connectors with maximum breaking strength
and has the input and the output connected by a superconducting wire.
A current
is circulating through the inductor.
- Is the force between the plates attractive or repulsive?
- What is the maximum magnetic field that the inductor can have between
the plates without blowing apart? Hint: Find the energy in the
magnetic field as a function of plate separation and compute the force
between the plates as for the capacitor. The magnetic flux through
the inductor remains constant as the plates move in this case, which
means that the current can change.
- What is the current corresponding to the above maximum field?
Figure 17.9:
Battery in parallel with an inductor.
 |
- Use Kirchhoff's laws to compute the net resistance of
- resistors in parallel, and
- resistors in series,
as shown in figure 17.10. Hint: In the first case the
voltage drop across the resistors is the same, in the second, the
current through the resistors is the same. Recall that Ohm's law
relates the current through a device to the voltage drop across it.
(If you already know the answers, derive them, don't just write them
down.)
Figure 17.10:
Resistors in parallel and in series.
 |
- Try to explain in physical terms why doubling the length of a resistor
doubles its resistance, while doubling its cross-sectional area halves
its resistance. Use this argument to justify equation
(17.17).
- Describe qualitatively what happens when
- the switch is closed in the circuit in figure 17.9, and
- when it is abruptly opened.
The battery produces a voltage difference
, but also may be thought
of as having a small internal resistance
.
Figure 17.11:
Circuit consisting of a shorted resistor.
 |
- Given the circuit shown in figure 17.11:
- What do Kirchhoff's laws tell you about
across the
resistor?
- Suppose a time-varying magnetic field
is
applied normal to the circuit loop, where
is a constant. What
is the (time-dependent) voltage drop
across the resistor
in this situation?
- Given the above
, what is the current through the
resistor as a function of time?
You may ignore the effect of the current in creating an additional
magnetic field.
David Raymond
2006-04-07