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Stationary and moving clocks run at different rates in relativity.
This is illustrated in figure 4.7. The triangle ABC in
the left panel of figure 4.7 can be used to illustrate
this point. Suppose that the line passing through the events A and
C in this figure is the world line of a stationary observer. At
zero time another observer moving with velocity
passes the
stationary observer. The moving observer's world line passes through
events A and B.
We assume that events B and C are simultaneous in the rest frame, so
ABC is a right triangle. Application of the spacetime Pythagorean
theorem thus yields
| (5.7) |
| (5.8) |
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(5.10) |
Equation (4.9) tells us that the time elapsed for the moving observer is less than that for the stationary observer, which means that the clock of the moving observer runs more slowly. This is called the time dilation effect.
Let us view this situation from the reference frame of the moving
observer. In this frame the moving observer becomes stationary and
the stationary observer moves in the opposite direction, as
illustrated in the right panel of figure 4.7. By symmetric
arguments, one infers that the clock of the initially stationary
observer who is now moving to the left runs more slowly in this
reference frame than the clock of the initially moving observer. One
might conclude that this contradicts the previous results. However,
examination of the right panel of figure 4.7 shows that
this is not so. The interval
is still greater than the interval
, because such intervals are relativistically invariant
quantities. However, events B and C are no longer simultaneous, so
one cannot use these results to infer anything about the rate at which
the two clocks run in this frame. Thus, the relative nature of the
concept of simultaneity saves us from an incipient paradox, and we see
that the relative rates at which clocks run depends on the reference
frame in which these rates are observed.
David Raymond 2006-04-07